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Theorems on angles formed by tangents and secants describe the relationships and properties of angles created when tangents and secants intersect a circle. These theorems are essential in geometry, particularly in the study of circles.Tangent-Secant Angle Theorem: The angle formed by a tangent and a secant (or chord) drawn from a point outside a circle is half the difference of the measures of the intercepted arcs.Secant-Secant Angle Theorem: The angle formed by two secants intersecting outside a circle is half the difference of the measures of the intercepted arcs.Tangent-Tangent Angle Theorem: The angle formed by two tangents intersecting outside a circle is half the difference of the measures of the intercepted arcs (which is also equal to half the measure of the difference between the two arcs).These theorems are useful in solving problems related to circle geometry, such as finding missing angle measures and proving other geometric properties.

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Download Theorems on Angles Formed by Tangents and Secants and more Slides Mathematics in PDF only on Docsity! Recall the tangents and secants on a circle; Find the measure of arcs, exterior angles, and interior angles of a circle; Value accumulated knowledge as means of new understanding. Objective s ae aATangents or, Secants? Use Q below to answer the following questions: ส˜ 3 At what points does each secant intersect the circle? In and In A Use Q below to answer the following questions: ส˜ At what points does each tangent intersects the circle? PointR and point P 4 Use Q below to answer the following questions: ส˜ Which angles are formed by two secant lines? 5 ยฟ๐ˆ๐“๐€ Use Q below to answer the following questions: ส˜ Name the intercepted arcs that these angles intercepts: 8 ยฟ๐‘๐ƒ๐ˆ ยฟ๐๐๐‚ ยฟ๐๐€๐‘ยฟ๐ˆ๐“๐ RI BC BR IP Find the measure of arcs, exterior angles and interior angles formed by tangents and secants Exterior Angles An exterior angle is formed by two secants, a secant and a tangent or a two tangents drawn from a point outside the circle. The vertex lies outside of the circle. Two secants A secant and a tangent Two tangents BC = DE = 110ยฐ ๐‘ฎ๐’Š๐’—๐’†๐’ : ยฟ๐‘ซ๐‘จ๐‘ฌ= ๐Ÿ ๐Ÿ ยฟ DE - BC ) ๐‘บ๐’๐’๐’–๐’•๐’Š๐’๐’ : ๐Ÿ’๐Ÿ–ยฐ=๐Ÿ ๐Ÿ ยฟ ๐Ÿ’๐Ÿ–ยฐ=๐Ÿ“๐Ÿ“ยฐโˆ’๐Ÿ๐Ÿ BC ) BC ๐Ÿ’๐Ÿ–ยฐ โˆ’๐Ÿ“๐Ÿ“ยฐ=โˆ’๐Ÿ๐Ÿ BC โˆ’๐Ÿ• ยฐ=โˆ’๐Ÿ๐Ÿ BC โˆ’๐Ÿ๐Ÿ โˆ’๐Ÿ๐Ÿ BC = 14ยฐ 14 ED = 200ยฐ EA = 40ยฐ ๐‘ฎ๐’Š๐’—๐’†๐’ : ยฟ๐‘ฌ๐‘ฉ๐‘ซ= ๐Ÿ ๐Ÿ ยฟ ED - AD ) ๐‘บ๐’๐’๐’–๐’•๐’Š๐’๐’ : ยฟ๐‘ฌ๐‘ฉ๐‘ซ= ๐Ÿ ๐Ÿ (๐Ÿ๐ŸŽ๐ŸŽยฐ โˆ’๐Ÿ๐Ÿ๐ŸŽยฐ ) 40 AD = 120 ยฟ๐‘ฌ๐‘ฉ๐‘ซ= ๐Ÿ ๐Ÿ (๐Ÿ–๐ŸŽยฐ) ยฟ๐‘ฌ๐‘ฉ๐‘ซ=๐Ÿ’๐ŸŽยฐ ABE = 265ยฐ AE = ยฟ ๐‘จ๐‘ซ๐‘ฌ=ยฟ ๐‘ฎ๐’Š๐’—๐’†๐’ : ยฟ ๐‘จ๐‘ซ๐‘ฌ= ๐Ÿ ๐Ÿ ยฟ ABE - AE ) ๐‘บ๐’๐’๐’–๐’•๐’Š๐’๐’ : ยฟ ๐‘จ๐‘ซ๐‘ฌ= ๐Ÿ ๐Ÿ (๐Ÿ๐Ÿ”๐Ÿ“ยฐ โˆ’๐Ÿ—๐Ÿ“ยฐ ) ยฟ ๐‘จ๐‘ซ๐‘ฌ= ๐Ÿ ๐Ÿ (๐Ÿ๐Ÿ•๐ŸŽยฐ ) ยฟ ๐‘จ๐‘ซ๐‘ฌ=๐Ÿ–๐Ÿ“ยฐ 85 ๐Ÿ—๐Ÿ“ยฐ Your turn! CA = (7x+4)ยฐ BE = (3x + 2)ยฐ ยฟ๐‘ช๐‘ซ๐‘จ=๐Ÿ’๐Ÿ“ยฐ ๐‘ฎ๐’Š๐’—๐’†๐’ : ยฟ๐‘ช๐‘ซ๐‘จ= ๐Ÿ ๐Ÿ ยฟ CA - BE ) ๐‘บ๐’๐’๐’–๐’•๐’Š๐’๐’ : 4 ๐‘ญ๐’Š๐’๐’… ๐’™ ,๐’‚๐’“๐’„ ๐‘ช๐‘จโˆง๐’‚๐’“๐’„ ๐‘ฉ๐‘ฌ 4 4 41 ๐’™=๐Ÿ๐Ÿ CA = [7(22)+4]ยฐ CA = CA = 158ยฐ BE = (3x + 2)ยฐ BE = 68ยฐ CA = (7x+4)ยฐ BE = [3(22)+2]ยฐ BE = 66 + 2 4 44 Interior Angles An interior angle can be formed by two chords or two secants that intersect inside of the circle. T T AB = 52ยฐ DE = xยฐ ยฟ ๐‘จ๐‘ช๐‘ฉ=๐Ÿ’๐ŸŽยฐ ๐‘ฎ๐’Š๐’—๐’†๐’ : ยฟ ๐‘จ๐‘ช๐‘ฉ= ๐Ÿ ๐Ÿ ยฟ BA + DE ) ๐‘บ๐’๐’๐’–๐’•๐’Š๐’๐’ : ๐Ÿ’๐ŸŽยฐ=๐Ÿ ๐Ÿ (๐Ÿ“๐Ÿยฐ+๐’™ ยฐ) ๐Ÿ’๐ŸŽยฐ=๐Ÿ๐Ÿ”ยฐ+๐Ÿ๐Ÿ ๐’™ ยฐ ๐Ÿ’๐ŸŽยฐ โˆ’๐Ÿ๐Ÿ”ยฐ=+๐Ÿ ๐Ÿ ๐’™ ยฐ ๐Ÿ๐Ÿ’ยฐ=๐Ÿ ๐Ÿ ๐’™ ยฐ ๐Ÿ ๐Ÿ ๐Ÿ ๐Ÿ ๐’™=๐Ÿ๐Ÿ–ยฐ ยฟ๐‘ฌ๐‘ช๐‘ซ=ยฟ ๐Ÿ’๐ŸŽยฐ NB = 107ยฐ AM = 19ยฐ ยฟ ๐‘จ๐‘ฟ๐‘ด=ยฟ ๐‘ฎ๐’Š๐’—๐’†๐’ : ยฟ ๐‘จ๐‘ฟ๐‘ด= ๐Ÿ ๐Ÿ ยฟ NB + AM ) ๐‘บ๐’๐’๐’–๐’•๐’Š๐’๐’ : ยฟ๐‘ต๐‘ฟ๐‘ฉ=ยฟ ยฟ ๐‘จ๐‘ฟ๐‘ด= ๐Ÿ ๐Ÿ (๐Ÿ๐Ÿ๐Ÿ”ยฐ ) ยฟ ๐‘จ๐‘ฟ๐‘ด=๐Ÿ”๐Ÿ‘ยฐ 63 ยฟ๐‘ด๐‘ฟ๐‘ฉ=๐Ÿ๐Ÿ–๐ŸŽยฐ โˆ’๐Ÿ”๐Ÿ‘ยฐ ยฟ๐‘ด๐‘ฟ๐‘ฉ=๐Ÿ๐Ÿ๐Ÿ•ยฐ 117ยฟ๐‘ด๐‘ฟ๐‘ฉ=ยฟ ยฟ ๐‘จ๐‘ฟ๐‘ต=ยฟ63 117 ยฟ ๐‘จ๐‘ฟ๐‘ด= ๐Ÿ ๐Ÿ ยฟ 107 + 19 ) AC = (3x+18)ยฐ DB = (x+10)ยฐ ยฟ๐Ÿ=๐Ÿ–๐ŸŽยฐ ๐‘ฎ๐’Š๐’—๐’†๐’ : ( AC + DB ) ๐‘บ๐’๐’๐’–๐’•๐’Š๐’๐’ : ๐Ÿ–๐ŸŽยฐ=๐Ÿ ๐Ÿ [(๐Ÿ‘ ๐’™+๐Ÿ๐Ÿ–)ยฐ+(๐’™+๐Ÿ๐ŸŽ)ยฐ ] ๐’™=ยฟ๐Ÿ‘๐Ÿ‘ยฟ๐Ÿ=ยฟ ๐Ÿ–๐ŸŽยฐ=๐Ÿ ๐Ÿ (๐Ÿ’ ๐’™+๐Ÿ๐Ÿ–)ยฐ ๐Ÿ–๐ŸŽยฐ=๐Ÿ ๐’™ ยฐ+๐Ÿ๐Ÿ’ยฐ ๐Ÿ ๐’™=๐Ÿ”๐Ÿ”ยฐ ๐’™=๐Ÿ‘๐Ÿ‘ AC = DB =๐Ÿ๐ŸŽ๐ŸŽยฐ AC = (3x+18)ยฐ AC = [3(33)+18]ยฐ AC = (99+18)ยฐ AC = 117ยฐ DB = (x+10)ยฐ DB = 43ยฐ DB = (33+10)ยฐ ๐Ÿ๐Ÿ๐Ÿ•ยฐ ๐Ÿ’๐Ÿ‘ยฐ ยฟ๐Ÿ= ๐Ÿ ๐Ÿ AC = (2x+17)ยฐ DB = (2x+3)ยฐ ยฟ๐Ÿ=๐Ÿ”๐ŸŽยฐ ๐‘ฎ๐’Š๐’—๐’†๐’ : AC + DB ) ๐‘บ๐’๐’๐’–๐’•๐’Š๐’๐’ : 6 ๐’™=ยฟ๐Ÿ๐Ÿ“ยฟ๐Ÿ=ยฟ 6 6 ๐Ÿ“๐ŸŽ=๐Ÿ ๐’™ 25 AC = DB =๐Ÿ๐Ÿ๐ŸŽยฐ AC = (2x+17)ยฐ AC = [2(25)+17]ยฐ AC = (50+17)ยฐ AC = 67ยฐ DB = (2x+3)ยฐ DB = 53ยฐ DB = (50+3)ยฐ ๐Ÿ”๐Ÿ•ยฐ ๐Ÿ“๐Ÿ‘ยฐ ยฟ๐Ÿ= ๐Ÿ ๐Ÿ( 6 DB = [2(25)+3)ยฐ Check your understanding _____ 1. If two secants intersect in the interior of the circle, then the angle formed is one-half the positive difference of the measures of the intercepted arcs. _____ 2. If two secants intersect in the exterior of the circle, then the angle formed is one-half the positive difference of the measures of the intercepted arcs. _____ 3. If two tangents intersect in the exterior of the circle, then the angle formed is one-half of the sums of the measures of the intercepted arcs. False Tell whether the following statement is true or false. True False Check your understanding _____ 4. An interior angle can be formed by two chords or two secants that intersect inside of the circle. _____ 5. The measure of the angle formed by the two chords or two secants is equal to ยฝ the sum of the measures of the intercepted arcs. _____ 6. An exterior angle is formed by two secants, a secant and a tangent or a two tangents drawn from a point outside the circle. Tell whether the following statement is true or false. True True True

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