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1 Chapter 4 Trigonometric Identities and Equations Trigonometric identities describe equalities between related trigonom...

Chapter 4

Trigonometric Identities and Equations Trigonometric identities describe equalities between related trigonometric expressions while trigonometric equations ask us to determine the specific values of the variables that make two expressions equal. Identities are tools that can be used to simplify complicated trigonometric expressions or solve trigonometric equations. In this chapter we will prove trigonometric identities and derive the double and half angle identities and sum and difference identities. We also develop methods for solving trigonometric equations, and learn how to use trigonometric identities to solve trigonometric equations.

4.1

Trigonometric Identities

Focus Questions The following questions are meant to guide our study of the material in this section. After studying this section, we should understand the concepts motivated by these questions and be able to write precise, coherent answers to these questions. What is an identity? How do we verify an identity? 244

4.1. Trigonometric Identities

245

Consider the trigonometric equation sin.2x/ D cos.x/. Based on our current knowledge, an equation like this can be difficult to solve exactly because the periods of the functions involved are different. What will allow us to solve this equation relatively easily is a trigonometric identity, and we will explicitly solve this equation in a subsequent section. This section is an introduction to trigonometric identities. As we discussed in Section 2.6, a mathematical equation like x 2 D 1 is a relation between two expressions that may be true for some values of the variable. To solve an equation means to find all of the values for the variables that make the two expressions equal to each other. An identity, is an equation that is true for all allowable values of the variable. For example, from previous algebra courses, we have seen that x 2 1 D .x C 1/.x 1/; for all real numbers x. This is an algebraic identity since it is true for all real number values of x. An example of a trigonometric identity is cos2 .x/ C sin2 .x/ D 1 since this is true for all real number values of x. So while we solve equations to determine when the equality is valid, there is no reason to solve an identity since the equality in an identity is always valid. Every identity is an equation, but not every equation is an identity. To know that an equation is an identity it is necessary to provide a convincing argument that the two expressions in the equation are always equal to each other. Such a convincing argument is called a proof and we use proofs to verify trigonometric identities. Definition. An identity is an equation that is true for all allowable values of the variables involved.

Beginning Activity 1. Use a graphing utility to draw the graph of y D cos x and y D 2 sin x C over the interval Œ 2; 2 on the same set of axes. Are the 2 two expressions cos x and sin x C the same – that is, do they 2 2 have the same value for every input x? If so, explain how the graphs indicate thatthe expressions are If not, find at least one value of x at which the same. cos x and sin x C have different values. 2 2

246

Chapter 4. Trigonometric Identities and Equations and y D 2 sin.x/ over the interval Œ 2; 2 on the same set of axes. Are the two expressions cos x and sin.x/ the same – that is, do they have the 2 same value for every input x? If so, explain how the graphs indicate that the expressions are the same. If not, find at least one value of x at which cos x and sin.x/ have different values. 2

2. Use a graphing utility to draw the graph of y D cos x

Some Known Trigonometric Identities We have already established some important trigonometric identities. We can use the following identities to help establish new identities. The Pythagorean Identity This identity is fundamental to the development of trigonometry. See page 18 in Section 1.2. For all real numbers t , cos2 .t / C sin2 .t / D 1. Identities from Definitions The definitions of the tangent, cotangent, secant, and cosecant functions were introduced in Section 1.6. The following are valid for all values of t for which the right side of each equation is defined. sin.t / cos.t / 1 sec.t / D cos.t / tan.t / D

cos.t / sin.t / 1 csc.t / D sin.t / cot.t / D

Negative Identities The negative were introduced in Chapter 2 when the symmetry of the graphs were discussed. (See page 82 and Exercise (2) on page 138.) cos. t / D cos.t /

sin. t / D

sin.t /

tan. t / D

tan.t /:

The negative identities for cosine and sine are valid for all real numbers t , and the negative identity for tangent is valid for all real numbers t for which tan.t / is defined.

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Verifying Identities Given two expressions, say tan2 .x/ C 1 and sec2 .x/, we would like to know if they are equal (that is, have the same values for every allowable input) or not. We can draw the graphs of y D tan2 .x/ C 1 and y D sec2 .x/ and see if the graphs look the same or different. Even if the graphs look the same, as they do with y D tan2 .x/C1 and y D sec2 .x/, that is only an indication that the two expressions are equal for every allowable input. In order to verify that the expressions are in fact always equal, we need to provide a convincing argument that works for all possible input. To do so we use facts that we know (existing identities) to show that two trigonometric expressions are always equal. As an example, we will verify that the equation tan2 .x/ C 1 D sec2 .x/ (1) is an identity. A proper format for this kind of argument is to choose one side of the equation and apply existing identities that we already know to transform the chosen side into the remaining side. It usually makes life easier to begin with the more complicated looking side (if there is one). In our example of equation (1) we might begin with the expression tan2 .x/ C 1. Example 4.1 (Verifying a Trigonometric Identity) To verify that equation (1) is an identity, we work with the expression tan2 .x/ C 1. It can often be a good idea to write all of the trigonometric functions in terms of sin.x/ the cosine and sine to start. In this case, we know that tan.x/ D , so we cos.x/ could begin by making this substitution to obtain the identity sin.x/ 2 2 tan .x/ C 1 D C 1: (2) cos.x/ Note that this is an identity and so is valid for all allowable values of the variable. Next we can apply the square to both the numerator and denominator of the right hand side of our identity (2).

sin.x/ cos.x/

2

C1D

sin2 .x/ C 1: cos2 .x/

(3)

Next we can perform some algebra to combine the two fractions on the right hand side of the identity (3) and obtain the new identity sin2 .x/ sin2 .x/ C cos2 .x/ C 1 D : cos2 .x/ cos2 .x/

(4)

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Chapter 4. Trigonometric Identities and Equations

Now we can recognize the Pythagorean identity cos2 .x/ C sin2 .x/ D 1, which makes the right side of identity (4) sin2 .x/ C cos2 .x/ 1 D : cos2 .x/ cos2 .x/

(5)

Recall that our goal is to verify identity (1), so we need to transform the expression 1 into sec2 .x/. Recall that sec.x/ D , and so the right side of identity (5) cos.x/ leads to the new identity 1 D sec2 .x/; 2 cos .x/ which verifies the identity. An argument like the one we just gave that shows that an equation is an identity is called a proof. We usually leave out most of the explanatory steps (the steps should be evident from the equations) and write a proof in one long string of identities as sin.x/ 2 2 tan .x/ C 1 D C1 cos.x/ sin2 .x/ D C1 cos2 .x/ sin2 .x/ C cos2 .x/ D cos2 .x/ 1 D cos2 .x/ D sec2 .x/: To prove an identity is to show that the expressions on each side of the equation are the same for every allowable input. We illustrated this process with the equation tan2 .x/ C 1 D sec2 .x/. To show that an equation isn’t an identity it is enough to demonstrate that the two sides of the equation have different values at one input. Example 4.2 (Showing that an Equation is not an Identity) Consider the equation with the equation cos x D sin x C that we 2 2 encountered in our Beginning Activity. Although you can check that cos x 2 and sin x C are equal at some values, for example, they are not equal at all 4 2 values – cos 0 D 0 but sin 0 C D 1. Since an identity must provide 2 2

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an equality for all allowable values of the variable, if the two expressions at differ D one input, then the equation is not an identity. So the equation cos x 2 sin x C is not an identity. 2 Example 4.2 illustrates an important point. to show that an equation is not an identity, it is enough to find one input at which the two sides of the equation are not equal. We summarize our work with identities as follows. To prove that an equation is an identity, we need to apply known identities to show that one side of the equation can be transformed into the other. To prove that an equation is not an identity, we need to find one input at which the two sides of the equation have different values. Important Note: When proving an identity it might be tempting to start working with the equation itself and manipulate both sides until you arrive at something you know to be true. DO NOT DO THIS! By working with both sides of the equation, we are making the assumption that the equation is an identity – but this assumes the very thing we need to show. So the proper format for a proof of a trigonometric identity is to choose one side of the equation and apply existing identities that we already know to transform the chosen side into the remaining side. It usually makes life easier to begin with the more complicated looking side (if there is one). Example 4.3 (Verifying an Identity) Consider the equation 2 cos2 .x/

1 D cos2 .x/

sin2 .x/:

Graphs of both sides appear to indicate that this equation is an identity. To prove the identity we start with the left hand side: 2 cos2 .x/

1 D cos2 .x/ C cos2 .x/ 2

D cos .x/ C .1 2

D cos .x/

1 2

sin .x//

1

2

sin .x/:

Notice that in our proof we rewrote the Pythagorean identity cos2 .x/Csin2 .x/ D 1 as cos2 .x/ D 1 sin2 .x/. Any proper rearrangement of an identity is also an identity, so we can manipulate known identities to use in our proofs as well.

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Chapter 4. Trigonometric Identities and Equations

To reiterate, the proper format for a proof of a trigonometric identity is to choose one side of the equation and apply existing identities that we already know to transform the chosen side into the remaining side. There are no hard and fast methods for proving identities – it is a bit of an art. You must practice to become good at it. Progress Check 4.4 (Verifying Identities) For each of the following use a graphing utility to graph both sides of the equation. If the graphs indicate that the equation is not an identity, find one value of x at which the two sides of the equation have different values. If the graphs indicate that the equation is an identity, verify the identity. 1.

sec2 .x/ 1 D sin2 .x/ sec2 .x/

2. cos.x/ sin.x/ D 2 sin.x/

Summary of Section 4.1 In this section, we studied the following important concepts and ideas: An identity is an equation that is true for all allowable values of the variables involved. To prove that an equation is an identity, we need to apply known identities to show that one side of the equation can be transformed into the other. To prove that an equation is not an identity, we need to find one input at which the two sides of the equation have different values.

Exercises for Section 4.1 1. Use a graphing utility to graph each side of the given equation. If the equation appears to be an identity, prove the identity. If the equation appears to not be an identity, demonstrate one input at which the two sides of the equation have different values. Remember that when proving an identity, work to transform one side of the equation into the other using known identities. Some general guidelines are I. Begin with the more complicated side.

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II. It is often helpful to use the definitions to rewrite all trigonometric functions in terms of the cosine and sine. III. When appropriate, factor or combine terms. For example, sin2 .x/ C 1 1 C cos.x/ can be sin.x/ can be written as sin.x/.sin.x/ C 1/ and sin.x/ written as the single fraction

cos.x/Csin.x/ sin.x/ cos.x/

with a common denominator.

IV. As you transform one side of the equation, keep the other side of the equation in mind and use identities that involve terms that are on the other side. For example, to verify that tan2 .x/ C 1 D cos21.x/ , start with tan2 .x/ C 1 and make use identities that relate tan.x/ to cos.x/ as closely as possible.

? ?

?

(a) cos.x/ tan.x/ D sin.x/ cot.s/ (b) D cos.s/ csc.s/ tan.s/ (c) D sin.s/ sec.s/ (d) cot2 .x/ C 1 D csc2 .x/

(e) sec2 .x/ C csc2 .x/ D 1

(f) cot.t / C 1 D csc.t /.cos.t / C sin.t // 1 (g) tan2 . /.1 C cot2 . // D 1 sin2 . / (h) (i)

1

sin2 .ˇ/ D sin.ˇ/ cos.ˇ/

1

sin2 .ˇ/ D cos.ˇ/ cos.ˇ/

(j) sin2 .x/ C tan2 .x/ C cos2 .x/ D sec2 .x/. 2. A student claims that cos. / C sin. / D 1 is an identity because cos.0/ C sin.0/ D 1 C 0 D 0. How would you respond to this student? 3. If a trigonometric equation has one solution, then the periodicity of the trigonometric functions implies that the equation will have infinitely many solutions. Suppose we have a trigonometric equation for which both sides of the equation are equal at infinitely many different inputs. Must the equation be an identity? Explain your reasoning.

252

4.2

Chapter 4. Trigonometric Identities and Equations

Trigonometric Equations

Focus Questions The following questions are meant to guide our study of the material in this section. After studying this section, we should understand the concepts motivated by these questions and be able to write precise, coherent answers to these questions. What is a trigonometric equation? What does it mean to solve a trigonometric equation? How is a trigonometric equation different from a trigonometric identity? We have already learned how to solve certain types of trigonometric equations. In Section 2.6 we learned how to use inverse trigonometric functions to solve trigonometric equations.

Beginning Activity Refer back to the method from Section 2.6 to find all solutions to the equation sin.x/ D 0:4.

Trigonometric Equations When a light ray from a point P reflects off a surface at a point R to illuminate a point Q as shown at left in Figure 4.1, the light makes two angles ˛ and ˇ with a perpendicular to the surface. The angle ˛ is called the angle of incidence and the angle ˇ is called the angle of reflection. The Law of Reflection states that when light is reflected off a surface, the angle of incidence equals the angle of reflection. What happens if the light travels through one medium (say air) from a point P , deflects into another medium (say water) to travel to a point Q? Think about what happens if you look at an object in a glass of water. See Figure 4.1 at right. Again the light makes two angles ˛ and ˇ with a perpendicular to the surface. The angle ˛ is called the angle of incidence and the angle ˇ is called the angle of refraction. If light travels from air into water, the Law of Refraction says that sin.˛/ ca D sin.ˇ/ cw

(6)

4.2. Trigonometric Equations

253 P

P

Q

Air

α

Water

R

β

α β R

Q

Figure 4.1: Reflection and refraction. where ca is the speed of light in air and cw is the speed of light in water. The ca of the speed of light in air to the speed of light in water can be calculated ratio cw by experiment. In practice, the speed of light in each medium is compared to the speed of light in a vacuum. The ratio of the speed of light in a vacuum to the speed of light in water is around 1.33. This is called the index of refraction for water. The index of refraction for air is very close to 1, so the ratio ccwa is close to 1.33. We can usually measure the angle of incidence, so the Law of Refraction can tells us what the angle of refraction is by solving equation (6). Trigonometric equations arise in a variety of situations, like in the Law of Refraction, and in a variety of disciplines including physics, chemistry, and engineering. As we develop trigonometric identities in this chapter, we will also use them to solve trigonometric equations. Recall that Equation (6) is a conditional equation because it is not true for all allowable values of the variable. To solve a conditional equation means to find all of the values for the variables that make the two expressions on either side of the equation equal to each other.

Equations of Linear Type Section 2.6 showed us how to solve trigonometric equations that are reducible to linear equations. We review that idea in our first example. Example 4.5 (Solving an Equation of Linear Type) Consider the equation 2 sin.x/ D 1: We want to find all values of x that satisfy this equation. Notice that this equation

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Chapter 4. Trigonometric Identities and Equations

looks a lot like the linear equation 2y D 1, with sin.x/ in place of y. So this trigonometric equation is of linear type and we say that it is linear in sin.x/. We know how to solve 2y D 1, we simply divide both sides of the equation by 2 to 1 obtain y D . We can apply the same algebraic operation to 2 sin.x/ D 1 to obtain 2 the equation 1 sin.x/ D : 2 Now we could proceed in a couple of ways. From previous work we know that 1 sin.x/ D when x D . Alternatively, we could apply the inverse sine to both 2 6 1 1 sides of our equation to see that one solution is x D sin D . 2 6 Recall, however, this is not the only solution. The first task is to find all of the solutions in one complete period of the sine function. We can use the interval with 0 x 2 but we often use the interval x . In this case, it makes no difference since the sine function is positive in the second quadrant. Using as a 6 5 reference angle, we see that x D D is another solution of this equation. 6 6 (Use a calculator to check this.) We now use the fact that the sine function is period with a period of 2 to write formulas that can be used to generate all solutions of the equation 2 sin.x/ D 1. So the angles in the first quadrant are C k.2/ and the angles in the second 6 5 quadrant are Ck.2/, where k is an integer. So for the solutions of the equation 6 2 sin.x/ D 1, we write xD

5 C k.2/ or x D C k.2/; 6 6

where k is an integer. We can always check our solutions by graphing both sides of the equation to see where the two expressions intersect. Figure 4.2 shows that graphs of y D 2 sin.x/ and y D 1 on the interval Œ 2; 3. We can see that the points of intersection of these two curves occur at exactly the solutions we found for this equation.

Progress Check 4.6 (Solving an Equation of Linear Type) p Find the exact values of all solutions to the equation 4 cos.x/ D 2 2. Do this by first finding all solutions in one complete period of the cosine function and

4.2. Trigonometric Equations

255

Figure 4.2: The graphs of y D 2 sin.x/ and y D 1 then using the periodic property to write formulas that can be used to generate all solutions of the equation. Draw appropriate graphs to illustrate your solutions.

Solving an Equation Using an Inverse Function When we solved the equation 2 sin.x/ D 1, we used the fact that we know that 1 sin D . When we cannot use one of the common arcs, we use the more 6 2 general method of using an inverse trigonometric function. This is what we did in Section 2.6. See “A Strategy for Solving a Trigonometric Function” on page 157. We will illustrate this strategy with the equation cos.x/ D 0:7. We start by applying the inverse cosine function to both sides of this equation to obtain

cos

1

cos.x/ D 0:7

.cos.x/ D cos

x D cos

1

.0:7/

1

.0:7/

This gives the one solution for the equation that is in interval Œ0; . Before we use the periodic property, we need to determine the other solutions for the equation in one complete period of the cosine function. We can use the interval Œ0; 2 but it is easier to use the interval Œ ; . One reason for this is the following so-called “negative arc identity” stated on page 82. cos. x/ D cos.x/ for every real number x:

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Chapter 4. Trigonometric Identities and Equations

Hence, since one solution for the equation is x D cos 1 .0:7/, another solution is x D cos 1 .0:7/. This means that the two solutions of the equation x D cos.x/ on the interval Œ ;  are x D cos

1

.0:7/ and x D

cos

1

.0:7/:

Since the period iof the cosine function is 2, we can say that any solution of the equation cos.x/ D 0:7 will be of the form x D cos

1

.0:7/ C k.2/

or x D

cos

1

.0:7/ C k.2/;

where k is some integer. Note: The beginning activity for this section had the equation sin.x/ D 0:4. The solutions for this equation are x D arcsin.0:4/ C k.2/ or x D .

arcsin.0:4// C k.2/;

where k is an integer. We can write the solutions in approximate form as x D 0:41152 C k.2/ or x D 2:73008 C k.2/; where k is an integer. Progress Check 4.7 (Solving Equations of Linear Type) 1. Determine formulas that can be used to generate all solutions to the equation 5 sin.x/ D 2. Draw appropriate graphs to illustrate your solutions in one period of the sine function. 2. Approximate, to two decimal places, the angle of refraction of light passing from air to water if the angle of incidence is 40ı.

Solving Trigonometric Equations Using Identities We can use known trigonometric identities to help us solve certain types of trigonometric equations. Example 4.8 (Using Identities to Solve Equations) Consider the trigonometric equation cos2 .x/

sin2 .x/ D 1:

(7)

4.2. Trigonometric Equations

257

This equation is complicated by the fact that there are two different trigonometric functions involved. In this case we use the Pythagorean Identity sin2 .x/ C cos2 .x/ D 1 by solving for cos2 .x/ to obtain cos2 .x/ D 1

sin2 .x/:

We can now substitute into equation (7) to get .1

sin2 .x//

sin2 .x/ D 1:

Note that everything is in terms of just the sine function and we can proceed to solve the equation from here: .1

sin2 .x// 1

sin2 .x/ D 1

2 sin2 .x/ D 1

2 sin2 .x/ D 0

sin2 .x/ D 0 sin.x/ D 0:

We know that sin.x/ D 0 when x D k for any integer k, so the solutions to the equation cos2 .x/ sin2 .x/ D 1 are x D k for any integer k: This is illustrated by Figure 4.3. Progress Check 4.9 (Using Identities to Solve Equations) Find the exact values of all solutions to the equation sin2 .x/ D 3 cos2 .x/. Draw appropriate graphs to illustrate your solutions.

Other Methods for Solving Trigonometric Equations Just like we did with linear equations, we can view some trigonometric equations as quadratic in nature and use tools from algebra to solve them.

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Chapter 4. Trigonometric Identities and Equations

Figure 4.3: The graphs of y D cos2 .x/

sin2 .x/ and y D 1

Example 4.10 (Solving Trigonometric Equations of Quadratic Type) Consider the trigonometric equation cos2 .x/

2 cos.x/ C 1 D 0:

This equation looks like a familiar quadratic equation y 2 2y C 1 D 0. We can solve this quadratic equation by factoring to obtain .y 1/2 D 0. So we can apply the same technique to the trigonometric equation cos2 .x/ 2 cos.x/ C 1 D 0. Factoring the left hand side yields .cos.x/

1/2 D 0:

The only way .cos.x/ 1/2 can be 0 is if cos.x/ 1 is 0. This reduces our quadratic trigonometric equation to a linear trigonometric equation. To summarize the process so far we have cos2 .x/

2 cos.x/ C 1 D 0

.cos.x/

cos.x/

1/2 D 0 1D0

cos.x/ D 1: We know that cos.x/ D 1 when x D 2k for integer values of k. Therefore, the solutions to our original equation are x D 2k

4.2. Trigonometric Equations

259

where k is any integer. As a check, the graph of y D cos2 .x/ 2 cos.x/ C 1 is shown in Figure 4.4. The figure appears to show that the graph of y D cos2 .x/ 2 cos.x/ C 1 intersects the x-axis at exactly the points we found, so our solution is validated by graphical means.

Figure 4.4: the graph of y D cos2 .x/

2 cos.x/ C 1

Progress Check 4.11 (Solving Trigonometric Equations of Quadratic Type) Find the exact values of all solutions to the equation sin2 .x/ 4 sin.x/ D 3. Draw appropriate graphs to illustrate your solutions.

Summary of Section 4.2 In this section, we studied the following important concepts and ideas: A trigonometric equation is a conditional equation that involves trigonometric functions. If it is possible to write the equation in the form “some trigonometric function of x” D a number;

(1)

we can use the following strategy to solve the equation: Find all solutions of the equation within one period of the function. This is often done by using properties of the trigonometric function. Quite often, there will be two solutions within a single period. Use the period of the function to express formulas for all solutions by adding integer multiples of the period to each solution found in the first step. For example, if the function has a period of 2 and x1 and x2 are the only two

260

Chapter 4. Trigonometric Identities and Equations solutions in a complete period, then we would write the solutions for the equation as x D x1 C k.2/;

x D x2 C k.2/; where k is an integer:

We can sometimes use trigonometric identities to help rewrite a given equation in the form of equation (1).

Exercises for Section 4.2 1. For each of the following equations, determine formulas that can be used to generate all solutions of the given equation. Use a graphing utility to graph each side of the given equation to check your solutions. ?

(a) 2 sin.x/

?

(b) 2 cos.x/ C 1 D 0 p (c) 2 sin.x/ C 2 D 0

?

(d) 4 cos.x/ 2

(e) 3 sin .x/ ?

1D0

3D0

2 sin.x/ D 0

(f) sin.x/ cos2 .x/ D 2 sin.x/

(g) cos2 .x/ C 4 sin.x/ D 4

(h) 5 cos.x/ C 4 D 2 sin2 .x/ (i) 3 tan2 .x/

(j)

tan2 .x/

1D0

tan.x/ D 6

2. A student is asked to approximate all solutions in degrees (to two decimal 1 places) to the equation sin. / C D 1 on the interval 0ı 360ı. 3 2 The student provides the answer D sin 1 41:81ı. Did the student 3 provide the correct answer to the stated problem? Explain. 3. X-ray crystallography is an important tool in chemistry. One application of X-ray crystallography is to discover the atomic structure macromolecules. For example, the double helical structure of DNA was found using X-ray crystallography. The basic idea behind X-ray crystallography is this: two X-ray beams with the same wavelength and phase are directed at an angle toward a crystal composed of atoms arranged in a lattice in planes separated by a distance d as illustrated in Figure 4.5.1 The beams reflect off different atoms (labeled as P and Q in Figure 4.5) within the crystal. One X-ray beam (the lower one as 1 The

symbol is the Greek lowercase letter ”lambda”.

4.2. Trigonometric Equations

261

illustrated in Figure 4.5) must travel a longer distance than the other. When reflected, the X-rays combine but, because of the phase shift of the lower beam, the combination might have a small amplitude or a large amplitude. Bragg’s Law states that the sum of the reflected rays will have maximum amplitude when the extra length the longer beam has to travel is equal to an integer multiple of the wavelength of the radiation. In other words, n D 2d sin. /; for some positive integer n. Assume that D 1:54 angstroms and d D 2:06 angstroms. Approximate to two decimal places the smallest value of (in degrees) for which n D 1.

P

d

h

θ Q

Figure 4.5: X-rays reflected from crystal atoms.

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4.3

Chapter 4. Trigonometric Identities and Equations

Sum and Difference Identities

Focus Questions The following questions are meant to guide our study of the material in this section. After studying this section, we should understand the concepts motivated by these questions and be able to write precise, coherent answers to these questions. What are the Cosine Difference and Sum Identities? What are the Sine Difference and Sum Identities? What are the Tangent Difference and Sum Identities? What are the Cofunction Identities? Why are the difference and sum identities useful? The next identities we will investigate are the sum and difference identities for the cosine and sine. These identities will help us find exact values for the trigonometric functions at many more angles and also provide a means to derive even more identities.

Beginning Activity 1. Is cos.A

B/ D cos.A/

2. Is sin.A

B/ D sin.A/

cos.B/ an identity? Explain. sin.B/ an identity? Explain.

3. Use a graphing utility to draw the graph of y D sin

x and y D

2 cos.x/ overthe interval Œ 2; 2 on the same set of axes. Do you think sin x D cos.x/ is an identity? Why or why not? 2

The Cosine Difference Identity To this point we know the exact values of the trigonometric functions at only a few angles. Trigonometric identities can help us extend this list of angles at which we know exact values of the trigonometric functions. Consider, for example, the problem of finding the exact value of cos . The definitions and identities 12 we have so far do not help us with this problem. However, we could notice that

4.3. Sum and Difference Identities

263

D and if we knew how the cosine behaved with respect to the difference 12 3 4 of two angles, then we could find cos . In our Beginning Activity, however, 12 we saw that the equation cos.A B/ D cos.A/ cos.B/ is not an identity, so we need to understand how to relate cos.A B/ to cosines and sines of A and B. We state the Cosine Difference Identity below. This identity is not obvious, and a verification of the identity is given later in this section. For now we focus on using the identity. Cosine Difference Identity For any real numbers A and B we have cos.A

B/ D cos.A/ cos.B/ C sin.A/ sin.B/:

Example 4.12 (Using the Cosine Difference Identity) Let us return to our problem of finding cos . Since we know D , 12 12 3 4 we can use the Cosine Difference Identity with A D and B D to obtain 3 4 cos D cos 12 3 4 D cos cos C sin sin 3 4 3 4 p ! p ! p ! 2 3 2 1 C D 2 2 2 2 p p 2C 6 : D 4 p p 2C 6 So we see that cos D . 12 4 Progress Check 4.13 (Using the Cosine Difference Identity) 7 1. Determine the exact value of cos using the Cosine Difference Iden12 tity. 5 2. Given that D C D , determine the exact value of 6 4 6 4 12 5 cos using the Cosine Difference Identity. 12

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Chapter 4. Trigonometric Identities and Equations

The Cosine Sum Identity Since there is a Cosine Difference Identity, we might expect there to be a Cosine Sum Identity. We can use the Cosine Difference Identity along with the negative identities to find an identity for cos.A C B/. The basic idea was contained in our last Progress Check, where we wrote A C B as A . B/. To see how this works in general, notice that cos.A C B/ D cos.A . B// D cos.A/ cos. B/ C sin.A/ sin. B/ D cos.A/ cos.B/

sin.A/ sin.B/:

This is the Cosine Sum Identity. Cosine Sum Identity For any real numbers A and B we have cos.A C B/ D cos.A/ cos.B/

sin.A/ sin.B/:

Progress Check 4.14 (Using the Cosine Sum and Difference Identities) 1. Find a simpler formula for cos . C x/ in terms of cos.x/. Illustrate with a graph. 2. Use the Cosine Difference Identity to prove that cos x D sin.x/ is 2 an identity.

Cofunction Identities

In Progress Check 4.14 we used the Cosine Difference Identity to see that cos x D 2 sin.x/ is an identity. Since this is an identity, we can replace x with x to see 2 that sin x D cos x D cos.x/; 2 2 2 so sin x D cos.x/. The two identities 2 cos x D sin.x/ and sin x D cos.x/ 2 2

are called cofunction identities. These two cofunction identities show that the sine and cosine of the acute angles in a right triangle are related in a particular way.

4.3. Sum and Difference Identities

265

Since the sum of the measures of the angles in a right triangle is radians or 180ı , the measures of the two acute angles in a right triangle sum to radians or 2 90ı . Such angles are said to be complementary. Thus, the sine of an acute angle in a right triangle is the same as the cosine of its complementary angle. For this reason we call the sine and cosine cofunctions. The naming of the six trigonometric functions reflects the fact that they come in three sets of cofunction pairs: the sine and cosine, the tangent and cotangent, and the secant and cosecant. The cofunction identities are the same for any cofunction pair. Cofunction Identities For any real number x for which the expressions are defined, cos x D sin.x/ 2 sin x D cos.x/ 2 x D cot.x/ tan 2 cot x D tan.x/ 2 sec x D csc.x/ 2 csc x D sec.x/ 2

For any angle x in degrees for which the functions are defined, cos .90ı

x/ D sin.x/

sin .90ı

x/ D cos.x/

tan .90ı

x/ D cot.x/

cot .90ı

x/ D tan.x/

sec .90ı

x/ D csc.x/

csc .90ı

x/ D sec.x/

Progress Check 4.15 (Using the Cofunction Identities) Use the cosine and sine cofuntion identities to prove the cofunction identity

tan

2

x D cot.x/:

The Sine Difference and Sum Identities We can now use the Cosine Difference Identity and the Cofunction Identities to derive a Sine Difference Identity:

266

Chapter 4. Trigonometric Identities and Equations

sin.A

B/ D cos

.A

B/

2 D cos A C B/ 2 D cos A cos.B/ sin A sin.B/ 2 2 D sin.A/ cos.B/ cos.A/ sin.B/:

We can derive a Sine Sum Identity from the Sine Difference Identity:

sin.A C B/ D sin.A . B// D sin.A/ cos. B/

cos.A/ sin. B/

D sin.A/ cos.B/ C cos.A/ sin.B/:

Sine Difference and Sum Identities For any real numbers A and B we have sin.A

B/ D sin.A/ cos.B/

cos.A/ sin.B/

and sin.A C B/ D sin.A/ cos.B/ C cos.A/ sin.B/: Progress Check 4.16 (Using the Sine Sum and Difference Identities) Use the Sine Sum or Difference Identities to find the exact values of the following. 1. sin

12

5 2. sin 12

Using Sum and Difference Identities to Solve Equations As we have done before, we can use our new identities to solve other types of trigonometric equations.

4.3. Sum and Difference Identities

267

Example 4.17 (Using the Cosine Sum Identity to Solve an Equation) Consider the equation p 3 cos. / cos sin. / sin D : 5 5 2

On the surface this equation looks quite complicated, but we can apply an identity to simplify it to the point where it is straightforward to solve. Notice that left side of this equation has the form cos.A/ cos.B/ sin.A/ sin.B/ with A D and B D . 5 We can use the Cosine Sum Identity cos.A C B/ D cos.A/ cos.B/ sin.A/ sin.B/ to combine the terms on the left into a single term, and we can solve the equation from there: p 3 cos. / cos sin. / sin D 5 5 p2 3 cos C D : 5 2 p 3 Now cos.x/ D when x D C 2k or x D C 2k for integers k. Thus, 2p 6 6 3 cos C D when C D C 2k or C D C 2k. Solving 5 2 5 6 5 6 for gives us the solutions D

C 2k or D 30

11 C 2k 30

where k is any integer. These solutions are illustrated in Figure 4.6. Note: Up to now, we have been using the phrase “Determine formulas that can be used to generate all the solutions of a given equation.” This is not standard terminology but was used to remind us of what we have to do to solve a trigonometric equation. We will now simply say, “Determine all solutions for the given equation.” When we see this, we should realize that we have to determine formulas that can be used to generate all the solutions of a given equation. Progress Check 4.18 (Using an Identity to Help Solve an Equation) Determine all solutions of the equation sin.x/ cos.1/ C cos.x/ sin.1/ D 0:2: Hint: Use a sum or difference identity and use the inverse sine function.

268

Chapter 4. Trigonometric Identities and Equations

Figure 4.6: Graphs of y D cos. / cos

5

sin. / sin

5

and y D

p

3 . 2

Appendix – Proof of the Cosine Difference Identity To understand how to calculate the cosine of the difference of two angles, let A and B be arbitrary angles in radians. Figure 4.7 shows these angles with A > B, but the argument works in general. If we plot the points where the terminal sides of the angles A, B, and A B intersect the unit circle, we obtain the picture in Figure 4.7. y (cos(A),sin(A))

(cos(B),sin(B)) (cos(A-B),sin(A-B)) A-B A-B

x

Figure 4.7: The cosine difference formula The arc on the unit circle from the point .cos.B/; sin.B// to the point .cos.A/; sin.A// has length A B, and the arc from the point (1,0) to the point .cos.A B/; sin.A B// also has length A B. So the chord from .cos.B/; sin.B//

4.3. Sum and Difference Identities

269

to .cos.A/; sin.A// has the same length as the chord from (1,0) to .cos.A B/; sin.A B//. To find the cosine difference formula, we calculate these two chord lengths using the distance formula. The length of the chord from .cos.B/; sin.B// to .cos.A/; sin.A// is q .cos.A/ cos.B//2 C .sin.A/ sin.B//2

and the length of the chord from (1,0) to .cos.A B/; sin.A B// is q .cos.A B/ 1/2 C .sin.A B/ 0/2 :

Since these two chord lengths are the same we obtain the equation q .cos.A B/ 1/2 C .sin.A B/ 0/2 q D .cos.A/ cos.B//2 C .sin.A/ sin.B//2 : (2) The cosine difference identity is found by simplifying Equation (2) by first squaring both sides:

.cos.A

1/2 C .sin.A

B/

B/

0/2

cos.B//2 C .sin.A/

D .cos.A/

sin.B//2 :

Then we expand both sides Œcos2 .A

B/

2 cos.A

B/ C 1 C sin2 .A

B/

D Œcos2 .A/ 2 cos.A/ cos.B/Ccos2 .B/CŒsin2 .A/ 2 sin.A/ sin.B/Csin2 .B/: We can combine some like terms: Œcos2 .A 2

B/ C sin2 .A 2

B/

2 cos.A

2

2

B/ C 1

D Œcos .A/Csin .A/CŒcos .B/Csin .B/ 2 cos.A/ cos.B/ 2 sin.A/ sin.B/: Finally, using the Pythagorean identities yields 1

2 cos.A

B/ C 1 D 1 C 1

2 cos.A cos.A

B/ D

2 cos.A/ cos.B/

2 cos.A/ cos.B/

2 sin.A/ sin.B/

2 sin.A/ sin.B/

B/ D cos.A/ cos.B/ C sin.A/ sin.B/:

Summary of Section 4.3 In this section, we studied the following important concepts and ideas:

270

Chapter 4. Trigonometric Identities and Equations

Sum and Difference Identities cos.A

B/ D cos.A/ cos.B/ C sin.A/ sin.B/

cos.A C B/ D cos.A/ cos.B/ sin.A

B/ D sin.A/ cos.B/

sin.A/ sin.B/

cos.A/ sin.B/

sin.A C B/ D sin.A/ cos.B/ C cos.A/ sin.B/ Cofunction Identities See page 265 for a list of the cofunction identities.

Exercises for Section 4.3 1. Use an appropriate sum or difference identity to find the exact value of each of the following. ?

(a) cos. 10ı / cos.35ı / C sin. 10ı / sin.35ı / 7 2 7 2 ? (b) cos cos sin sin 9 9 9 9 7 2 7 2 (c) sin cos C cos sin 9 9 9 9 ı ı ı ı (d) tan.80 / C tan.55 /1 tan.80 / tan.55 / 1 2. Angles A and B are in standard position and sin.A/ D , cos.A/ > 0, 2 3 cos.B/ D , and sin.B/ < 0. Draw a picture of the angles A and B in the 4 plane and then find each of the following. ?

(a) cos.A C B/

(b) cos.A

B/

(c) sin.A C B/

(d) sin.A

B/

(e) tan.A C B/ (f) tan.A

B/

3. Identify angles A and B at which we know the values of the cosine and sine so that a sum or difference identity can be used to calculate the exact value of the given quantity. (For example, 15ı D 45ı 30ı.)

4.3. Sum and Difference Identities ?

271

(a) cos.15ı/ (b) sin.75ı / (c) tan.105ı/

?

(d) sec.345ı/

4. Verify the sum and difference identities for the tangent: B/ D

tan.A/ tan.B/ 1 C tan.A/ tan.B/

tan.A C B/ D

tan.A/ C tan.B/ 1 tan.A/ tan.B/

tan.A and

. 5. Verify the cofunction identities ? (a) cot x D tan.x/ 2 (b) sec x D csc.x/ 2 (c) csc x D sec.x/ 2

6. Draw graphs to determine if a given equation is an identity. Verify those equations that are identities and provide examples to show that the others are not identities. C sin x D 2 sin.x/ cos (a) sin x C 4 4 4 ı ı (b) sin.210 C x/ cos.210 C x/ D 0

7. Determine if the following equations are identities. sin.r C s/ D tan.r/ C tan.s/ cos.r/ cos.s/ sin.s r/ (b) D tan.r/ tan.s/ cos.r/ cos.s/ (a)

8. Use an appropriate identity to solve the given equation. (a) sin. / cos .35ı / C cos. / sin .35ı / D (b) cos.2x/ cos.x/ C sin.2x/ sin.x/ D

1 2 1

272

Chapter 4. Trigonometric Identities and Equations

9. When two voltages are applied to a circuit, the resulting voltage in the circuit will be the sum of the individual voltages. Suppose two voltages V1 .t / D 30 sin.120 t / and V2 .t / D 40 cos.120 t / are applied to a circuit. The graph of the sum V .t / D V1 .t / C V2 .t / is shown in Figure 4.8.

Figure 4.8: Graph of V .t / D V1 .t / C V2 .t /. (a) Use the graph to estimate the values of C so that y D 50 sin.120.t

C //

fits the graph of V . (b) Use the Sine Difference Identity to rewrite 50 sin.120.t C // as an expression of the form 50 sin.A/ cos.B/ 50 cos.A/ sin.B/, where A and B involve t and/or C . From this, determine a value of C that will make 30 sin.120 t / C 40 cos.120 t / D 50 sin.120.t

C //:

Compare this value of C to the one you estimated in part (a).

4.4. Double and Half Angle Identities

4.4

273

Double and Half Angle Identities

Focus Questions The following questions are meant to guide our study of the material in this section. After studying this section, we should understand the concepts motivated by these questions and be able to write precise, coherent answers to these questions. What are the Double Angle Identities for the sine, cosine, and tangent? What are the Half Angle Identities for the sine, cosine, and tangent? What are the Product-to-Sum Identities for the sine and cosine? What are the Sum-to-Product Identities for the sine and cosine? Why are these identities useful? The sum and difference identities can be used to derive the double and half angle identities as well as other identities, and we will see how in this section. Again, these identities allow us to determine exact values for the trigonometric functions at more points and also provide tools for solving trigonometric equations (as we will see later).

Beginning Activity 1. Use B D A in the Cosine Sum Identity cos.A C B/ D cos.A/ cos.B/

sin.A/ sin.B/

to write cos.2A/ in terms of cos.A/ and sin.A/. 2. Is the equation cos.2x/ D cos.x/ 2 an identity? Verify your answer.

The Double Angle Identities Suppose a marksman is shooting a gun with muzzle velocity v0 D 1200 feet per second at a target 1000 feet away. If we neglect all forces acting on the bullet except

274

Chapter 4. Trigonometric Identities and Equations

the force due to gravity, the horizontal distance the bullet will travel depends on the angle at which the gun is fired. If we let r be this horizontal distance (called the range), then rD

v02 sin.2 /; g

where g is the gravitational force acting to pull the bullet downward. In this context, g D 32 feet per second squared, giving us r D 45000 sin.2 /: The marksman would want to know the minimum angle at which he should fire in order to hit the target 1000 feet away. In other words, the marksman wants to determine the angle so that r D 1000. This leads to solving the equation 45000 sin.2 / D 1000:

(3)

Equations like the range equation in which multiples of angles arise frequently, and in this section we will determine formulas for cos.2A/ and sin.2A/ in terms of cos.A/ and sin.A/. These formulas are called double angle identities. In our Beginning Activity we found that cos.2A/ D cos2 .A/

sin2 .A/

can be derived directly from the Cosine Sum Identity. A similar identity for the sine can be found using the Sine Sum Identity: sin.2A/ D sin.A C A/

D sin.A/ cos.A/ C cos.A/ sin.A/

D 2 cos.A/ sin.A/:

Progress Check 4.19 (Using the Double Angle Identities) 5 3 If cos. / D and 2, find cos.2 / and sin.2 /. 13 2 There is also a double angle identity for the tangent. We leave the verification of that identity for the exercises. To summarize:

4.4. Double and Half Angle Identities

275

Double Angle Identities cos.2A/ D cos2 .A/ sin2 .A/ sin.2A/ D 2 cos.A/ sin.A/ 2 tan.A/ tan.2A/ D ; 1 tan2 .A/ The first two identities are valid for all numbers A and the third is valid as long as A ¤ C k , where k is an integer. 4 2 Progress Check 4.20 (Alternate Double Angle Identities) Prove the alternate versions of the double angle identity for the cosine. 1. cos.2A/ D 1

2 sin2 .A/

2. cos.2A/ D 2 cos2 .A/

1.

Solving Equations with Double Angles Solving equations, like 45000 sin.2 / D 1000, that involve multiples of angles, requires the same kind of techniques as solving other equations, but the multiple angle can add another wrinkle. Example 4.21 (Solving an Equation with a Multiple Angle) Consider the equation 2 cos.2 / 1 D 0:

This is an equation that is linear in cos.2 /, so we can apply the same ideas as we did earlier to this equation. We solve for cos.2 / to see that 1 cos.2 / D : 2 1 We know the angles at which the cosine has the value , namely C 2k and 2 3 C 2k for integers k. In our case, this make 3 2 D C 2k or 2 D C 2k 3 3 for integers k. Now we divide by 2 to find our solutions D C k or D C k 6 6

276

Chapter 4. Trigonometric Identities and Equations

for integers k. These solutions are illustrated in Figure 4.9.

Figure 4.9: Graphs of y D 2 cos.2 /

1.

Progress Check 4.22 (Solving Equations with Double Angles) Approximate the smallest positive solution in degrees, to two decimal places, to the range equation 45000 sin.2 / D 1000: We can also use the Double Angle Identities to solve equations with multiple angles. Example 4.23 (Solving an Equation with a Double Angle Identity) Consider the equation sin.2 / D sin. /:

The fact that the two trigonometric functions have different periods makes this equation a little more difficult. We can use the Double Angle Identity for the sine to rewrite the equation as 2 sin. / cos. / D sin. /: At this point we may be tempted to cancel the factor of sin. / from both sides, but we should resist that temptation because sin. / can be 0 and we can’t divide by 0. Instead, let’s put everything one one side and factor: 2 sin. / cos. / D sin. /

2 sin. / cos. /

sin. / D 0

sin. /.2 cos. /

1/ D 0:

4.4. Double and Half Angle Identities

277

Now we have a product that is equal to 0, so at least one of the factors must be 0. This yields the two equations sin. / D 0 or cos. /

1 D 0:

We solve each equation in turn. We know that sin. / D 0 when D k for integers k. Also, cos. / 1 D 0 implies cos. / D 1, and this happens when D 2k for integers k. Notice that these solutions are a subset of the collection k of solutions of sin. / D 0. Thus, the solutions to sin.2 / D sin. / are D k for integers k, as illustrated in Figure 4.10.

Figure 4.10: Graphs of y D sin.2 / and y D sin. /. Progress Check 4.24 (Solving an Equation with a Double Angle Identity) The goal is to solve the equation cos.2 / D sin. /. 1. Use a double angle identity to help rewrite the equation in the form 2 sin2 . / C sin. /

1 D 0:

2. Solve the quadratic type equation in (1) by factoring the left side of the equation.

278

Chapter 4. Trigonometric Identities and Equations

Half Angle Identities A A Now we investigate the half angle identities, identities for cos and sin . 2 2 Here we use the double angle identities from Progress Check 4.20: A cos.A/ D cos 2 2 A cos.A/ D 2 cos2 1 2 A cos.A/ C 1 D 2 cos2 2 A cos.A/ C 1 cos2 D 2 2 r A 1 C cos.A/ D˙ : cos 2 2 A A The sign of cos depends on the quadrant in which lies. 2 2 Example 4.25 (Using the Cosine Half Angle Identity)

7 We can use the Cosine Half Angle Identity to determine the exact value of cos . 12 7 A 7 , then we have D . The Cosine Half Angle Identity shows If we let A D 6 12 2 us that ! 7 7 6 cos D cos 12 2 s 1 C cos 7 6 D˙ 2 s p 3 1 2 D˙ 2 s p 2 3 D˙ : 4 Since the terminal side of the angle

7 lies in the second quadrant, we know that 12

4.4. Double and Half Angle Identities

7 cos 12

279

is negative. Therefore,

7 cos 12

D

s

2

p 3 : 4

We can find a similar half angle formula for the sine using the same approach: A cos.A/ D cos 2 2 2 A cos.A/ D 1 2 sin 2 A cos.A/ 1 D 2 sin2 2 A 1 cos.A/ sin2 D 2 2 r A 1 cos.A/ sin D˙ : 2 2 Again, the sign of sin A depends on the quadrant in which A lies. 2 2 To summarize,

Half Angle Identities For any number A we have r A 1 C cos.A/ cos D˙ 2 2 r A 1 cos.A/ sin D˙ 2 2 where the sign depends on the quadrant in which

A lies. 2

Progress Check 4.26 (Using the Half Angle Identities) Use a Half Angle Identity to find the exact value of cos . 8

Summary of Section 4.4 In this section, we studied the following important concepts and ideas:

280

Chapter 4. Trigonometric Identities and Equations

Double Angle Identities cos.2A/ D cos2 .A/

sin2 .A/

cos.2A/ D 2 cos2 .A/

1

sin.2A/ D 2 cos.A/ sin.A/ 2 tan.A/ tan.2A/ D 1 tan2 .A/

2 sin2 .A/

cos.2A/ D 1

Half Angle Identities r A 1 C cos.A/ cos D˙ 2 2

r A 1 sin D˙ 2

where the sign depends on the quadrant in which

cos.A/ 2

A lies. 2

Exercises for Section 4.4 ?

1. Given that cos. / D

2 and sin. / < 0, find sin.2 /, cos.2 /, and tan.2 /. 3

2. Find all solutions to the given equation. Use a graphing utility to graph each side of the given equation to check your solutions. ?

1 2 (b) cos.2x/ C 3 D 5 cos.x/ (a) cos.x/ sin.x/ D

3. Determine which of the following equations is an identity. Verify your responses. ?

(a) cot.t / sin.2t / D 1 C cos.2t / (b) sin.2x/ D (c) cos.2x/ D

2

csc2 .x/ csc2 .x/

2

sec2 .x/ sec2 .x/

4. Find a simpler formula for cos . C x/ in terms of cos.x/. Illustrate with a graph.

4.4. Double and Half Angle Identities

281

5. A classmate shares his solution to the problem of solving sin.2x/ D 2 cos.x/ over the interval Œ0; 2/. He has written sin.2x/ D 2 cos.x/ sin.2x/ D cos.x/ 2 sin.x/ D cos.x/ tan.x/ D 1;

so x D

5 or x D . 4 4

(a) Draw graphs of sin.2x/ and 2 cos.x/ and explain why this classmates solution is incorrect. (b) Find the error in this classmate’s argument. (c) Determine the solutions to sin.2x/ D 2 cos.x/ over the interval Œ0; 2/. 6. Derive the Triple Angle Identity sin.3A/ D

4 sin3 .A/ C 3 sin.A/

for the sine with the following steps. (a) Write 3A as 2AxCAx and apply the Sine Sum Identity to write sin.3A/ in terms of sin.2A/ and sin.A/. (b) Use the Double Angle Identity for the sine to write sin.2A/ in terms of sin.A/ and cos.A/. (c) Use a Pythagorean Identity to write cos2 .A/ in terms of sin2 .A/ and simplify.

282

4.5

Chapter 4. Trigonometric Identities and Equations

Sum-Product Identities

Focus Questions The following questions are meant to guide our study of the material in this section. After studying this section, we should understand the concepts motivated by these questions and be able to write precise, coherent answers to these questions. What are the Product-to-Sum Identities for the sine and cosine? What are the Sum-to-Product Identities for the sine and cosine? Why are these identities useful? In general, trigonometric equations are very difficult to solve exactly. We have been using identities to solve trigonometric equations, but there are still many more for which we cannot find exact solutions. Consider, for example, the equation sin.3x/ C sin.x/ D 0: The graph of y D sin.3x/ C sin.x/ is shown in Figure 4.11. We can see that there are many solutions, but the identities we have so far do not help us with this equation. What would make this equation easier to solve is if we could rewrite the sum on the left as a product – then we could use the fact that a product is zero if and only if one of its factors is 0. We will later introduce the Sum-to-Product Identities that will help us solve this equation.

Beginning Activity 1. Let A D 30ı and B D 45ı . Calculate 1 cos.A/ cos.B/ and Œcos.A C B/ C cos.A 2

B/

What do you notice?

Product-to-Sum Identities The Cosine Sum and Difference Identities cos.A

B/ D cos.A/ cos.B/ C sin.A/ sin.B/

cos.A C B/ D cos.A/ cos.B/

sin.A/ sin.B/

(4) (5)

4.5. Sum-Product Identities

283

Figure 4.11: Graph of y D sin.3x/ C sin.x/. will allow us to develop identities that will express product of cosines or sines in terms of sums of cosines and sines. To see how these identities arise, we add the left and right sides of (4) and (5) to obtain cos.A So

B/ C cos.A C B/ D 2 cos.A/ cos.B/:

1 Œcos.A C B/ C cos.A cos.A/ cos.B/ D 2

B/ :

Similarly, subtracting the left and right sides of (5) from (4) gives us cos.A

B/

So sin.A/ sin.B/ D

cos.A C B/ D 2 sin.A/ sin.B/: 1 Œcos.A 2

B/

cos.A C B/ :

We can similarly obtain a formula for cos.A/ sin.B/. In this case we use the sine sum and difference formulas sin.A

B/ D sin.A/ cos.B/

cos.A/ sin.B/

sin.A C B/ D sin.A/ cos.B/ C cos.A/ sin.B/: Adding the left and right hand sides of (6) and (7) yields sin.A

B/ C sin.A C B/ D 2 sin.A/ cos.B/:

(6) (7)

284 So

Chapter 4. Trigonometric Identities and Equations

1 sin.A/ cos.B/ D Œsin.A C B/ C sin.A 2

B/ :

Product-to-Sum Identities For any numbers A and B we have 1 cos.A/ cos.B/ D Œcos.A C B/ C cos.A B/ 2 1 sin.A/ sin.B/ D Œcos.A B/ cos.A C B/ 2 1 Œsin.A C B/ C sin.A B/ : sin.A/ cos.B/ D 2 Progress Check 4.27 (Using the Sum-to-Product Identities) Find the exact value of sin .52:5ı/ sin .7:5ı /.

Sum-to-Product Identities As our final identities, we derive the reverse of the Product-to-Sum identities. These identities are called the Sum-to-Product identities. For example, to verify the identity ACB A B cos.A/ C cos.B/ D 2 cos cos ; 2 2 we first note that A D

ACB 2

C

A B 2

and B D

ACB A B cos.A/ D cos C 2 2 ACB A B D cos cos 2 2

ACB 2

A B 2 .

ACB sin 2

So

sin

A

B 2

(8)

and ACB A B cos.B/ D cos 2 2 A B ACB A B ACB D cos cos C sin sin : 2 2 2 2

(9)

4.5. Sum-Product Identities

285

Adding the left and right sides of (8) and (9) results in ACB A B cos.A/ C cos.B/ D 2 cos cos : 2 2 Also, if we subtract the left and right hands sides of (9) from (8) we obtain ACB A B cos.A/ cos.B/ D 2 sin sin : 2 2 Similarly,

ACB A B sin.A/ D sin C 2 2 A B ACB A B ACB cos C cos sin D sin 2 2 2 2

(10)

and ACB A B sin.B/ D sin 2 2 A B ACB D sin cos 2 2

cos

ACB 2

sin

A

B 2

:

(11)

Adding the left and right sides of (10) and (11) results in ACB A B sin.A/ C sin.B/ D 2 sin cos : 2 2 Again, if we subtract the left and right hands sides of (11) from (10) we obtain ACB A B sin.A/ sin.B/ D 2 cos sin : 2 2 Sum-to-Product Identities For any numbers A and B we have ACB A B cos 2 2 ACB A B cos.A/ cos.B/ D 2 sin sin 2 2 ACB A B sin.A/ C sin.B/ D 2 sin cos 2 2 ACB A B sin.A/ sin.B/ D 2 cos sin : 2 2

cos.A/ C cos.B/ D 2 cos

286

Chapter 4. Trigonometric Identities and Equations

Progress Check 4.28 (Using the Sum-to-Product Identities) Find the exact value of cos .112:5ı / C cos .67:5ı /. We can use these Sum-to-Product and Product-to-Sum Identities to solve even more types of trigonometric equations. Example 4.29 (Solving Equations Using the Sum-to-Product Identity) Let us return to the problem stated at the beginning of this section to solve the equation sin.3x/ C sin.x/ D 0: Using the Sum-to-Product sin.A/ C sin.B/ D 2 sin

ACB 2

cos

A

B 2

with A D x and B D 3x we can rewrite the equation as follows: sin.3x/ C sin.x/ D 0 x 4x cos D0 2 sin 2 2 x D 0: 2 sin.2x/ cos 2

The advantage of this form is that we now have a product of functions equal to 0, and the only way a product can equal 0 is if one of the factors is 0. This reduces our original problem to two equations we can solve: x sin.2x/ D 0 or cos D 0: 2 We know that sin.2x/ D 0 when 2x D k or x D k , where k is any integer, 2 x x and cos D 0 when D C k or x D C k2, where k is any integer. 2 2 2 These solutions can be seen where the graph of y D sin.3x/ C sin.x/ intersects the x-axis as illustrated in Figure 4.12.

Summary of Trigonometric Identities Trigonometric identities are useful in that they allow us to determine exact values for the trigonometric functions at more points than before and also provide tools for deriving new identities and for solving trigonometric equations. Here we provide a summary of our trigonometric identities.

4.5. Sum-Product Identities

287

Figure 4.12: Graph of y D sin.3x/ C sin.x/. Cofunction Identities cos sin tan

A D sin.A/ A D cos.A/ A D cot.A/:

2 2 2

Double Angle Identities sin.2A/ D 2 cos.A/ sin.A/

cos.2A/ D cos2 .A/ cos.2A/ D 1

sin2 .A/

2 sin2 .A/

cos.2A/ D 2 cos2 .A/ 1 2 tan.A/ : tan.2A/ D 1 tan2 .A/

Half Angle Identities 1 C cos.A/ 2 A cos D 2 2 r A 1 C cos.A/ cos D˙ 2 2 A 1 cos.A/ sin2 D 2 2 r A 1 cos.A/ sin D˙ 2 2 A sin.A/ tan D 2 1 C cos.A/ A 1 cos.A/ tan D : 2 sin.A/ A A The signs of cos and sin de2 2 pend on the quadrant in which A 2 lies.

Cosine Difference and Sum Identities cos.A

B/ D cos.A/ cos.B/ C sin.A/ sin.B/

cos.A C B/ D cos.A/ cos.B/

sin.A/ sin.B/:

288

Chapter 4. Trigonometric Identities and Equations

Sine Difference and Sum Identities sin.A

B/ D sin.A/ cos.B/

cos.A/ sin.B/

sin.A C B/ D sin.A/ cos.B/ C cos.A/ sin.B/: Tangent Difference and Sum Identities tan.A/ tan.B/ 1 C tan.A/ tan.B/ tan.A/ C tan.B/ tan.A C B/ D : 1 tan.A/ tan.B/ tan.A

B/ D

Product-to-Sum Identities 1 Œcos.A C B/ C cos.A B/ 2 1 sin.A/ sin.B/ D Œcos.A B/ cos.A B/ 2 1 sin.A/ cos.B/ D Œsin.A C B/ C sin.A B/ : 2

cos.A/ cos.B/ D

Sum-to-Product Identities A B ACB cos cos.A/ C cos.B/ D 2 cos 2 2 ACB A B cos.A/ cos.B/ D 2 sin sin 2 2 ACB A B sin.A/ C sin.B/ D 2 sin cos 2 2 ACB A B sin.A/ sin.B/ D 2 cos sin : 2 2

Exercises for Section 4.5 1. Find all solutions to the given equation. Use a graphing utility to graph each side of the given equation to check your solutions. (a) sin.x/ C sin.2x/ D

1 2

4.5. Sum-Product Identities 1 4 (c) cos.2x/ C cos.x/ D 0

(b) sin.x/ cos.x/ D

289

[PDF] Trigonometric Identities and Equations - Free Download PDF (2024)

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